the ln of x is no more complex, than cooking or tying a shoe

just find the power to which e should be raised, to equal the x in your queue

now e may seem quirky, this two point seven one thing

but it’s just another constant, with an infinite decimal string

***some natural log basics***

*ln(x) = some number for x>0**ln(x<0) = undefined**ln(0) = undefined (though it approaches negative infinity as x approaches 0 from the right)**ln(1) = 0**ln(e) = 1**ln(x*y) = ln(x) + ln (y)**ln(x/y) = ln(x) – ln (y)**ln(x^y) = y * ln(x)*

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